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A 14-16 NT ; two suited double (4 cd major longer minor) ; redouble (penalty); 2♦ (Bid your major); p; 2♠ ; 3♣ ;p;3NT. A low diamond is led, won by the J♦ . What next?
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There are plenty of tricks, 3 spades, three hearts, two diamonds, two clubs. But declarer must lose two tricks A♥ ,A♠ along the way. West cannot have both. With Axxx Ax KQxxx xx he would have opened the bidding. So, which one does he have, and why is it important? It's important because its the only entry to west's hand outside of diamonds and it must be extracted first. Whoever wins will likely continue diamonds setting up three tricks.
Declarer is not sure which Ace west holds, but from the bidding it is likely the A♠ . Therefore, a spade to the Q, and if not covered, a club back to the K♣ . Now drive out the A♠ Whether west gets out with K♦ or club, declarer will come to 10 tricks.
Whether declaring, or defending, be sure to listen to the bidding! |
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| Feel The Bern vs TaNNK Oct. 19 Board 11 |
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Here's a hand from a recent online match between Feel the Bern (Bern Reyberg, Jeff Billheimer, Melody Henderson, Mark Henderson), and TaNNK (Tom Denny, Nancy Ferguson, Tom Tully, Karen Pollak). At one table declarer received a Q♣ lead and eventually was down 1. At the other table south led the J♠ (partners suit) and play proceeded ♠ J610A, ♦ QK23, ♠ 78Q4, ♠K♠5 ♦5 ♠9, ♦4 ♥2 ♥4 ♦6, ♥ 6310A, ♥K ♥7 ♦7 ♥5, ♥Q ♥8 ♦9 ♥9.
With 5 cards left declarer needs four tricks, holding ♥J ♣5432, dummy ♦J ♣AK97. If clubs were 3-2 this would be no fun! What's your plan, and why?
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