Play Problem 005 - contributed by Graham Broadbent |
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You are South. You open a routine 2NT and, with opponents silent throughout, the auction continues 3clubs* - 3spades – 4spades – what now?
At our table I took the view that, with no five card suit and no extra values, I had bid my hand so passed.
Opening lead was 10 and Partner tabled the following: ♠KQJ8 ♥953 ♦J3 ♣ 9842. Would your partnership have bid the slam? And would you have made it?
* 3clubs is simple Stayman
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Show Answer |
The Answer
The full deal (hands rotated) Opening lead diamond 10
N/S Vulnerable
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KQJ8
953
J3
9842
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432
QJ42
10987
65
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97
K10876
K52
QJ3
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A1065
A
AQ64
AK107
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The 10 of diamonds goes to the 3, King and Ace. Draw trumps in 3 rounds, cash the Jack of diamonds and run the 9 of clubs. The club suit now comes in for four winners. Cash the Ace of hearts and the Queen of diamonds, discarding a heart from dummy. Ruff the last diamond with dummy’s final trump, leaving the final trick to the remaining trump in your hand. 13 tricks.
Not a good grand slam you would want to be in! But how does the partnership find the perfectly reasonable small slam, with only 28 HCP between the hands and no five-card suit?
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Re: Play Problems 005 contributed by Graham Broadbent |
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Play Problems 005 and 006 were inspired by duplicate boards in play at the club on 29 April. Graham made the following additional comment when submitting them:
"Last night's boards were full of interesting deals and no less than six slams available. These two presented partnership tests for N/S."
If you played that evening and want to check what contract your pair played in, use the Results menu to look up the 29 April event data. Click on your pair names to see your score card. Play Problem 005 was board 15 | |
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